A week after being named a finalist for the NBA’s Rookie of the Year award, Boston Celtics wing Jayson Tatum was voted to the league’s All-Rookie First Team.
Boston’s 20-year-old No. 3 overall pick averaged 13.9 points per game on 47.5/43.4/82.6 shooting splits. Tatum added five rebounds, 1.6 assists and a steal in 30.5 minutes a night. He played and started in 80 regular-season games
According to a release by the Celtics, Tatum’s scoring average was the highest by a Celtics rookie since Paul Pierce (16.5 ppg) in 1998-99. The release continued;
“Tatum thrived from beyond the arc in his inaugural campaign, setting franchise rookie records with 105 3-point field goals and a shooting percentage of 43.4 percent (fifth-highest among rookies in NBA history). He was the fifth rookie in NBA history and the first since Stephen Curry in 2009-10 to record more than 1,000 points and shoot at least 40 percent from three.”
The Duke product from St. Louis, Missouri has only gotten better in the postseason.
Tatum is Boston’s leading scorer in the playoffs with 18 points per game over 16 contests. His streak of seven straight games with 20 or more points was the longest such streak by any Celtics rookie in franchise history.
Tatum is also the first Celtics player to earn first team honors since Pierce. Current second-year player Jaylen Brown was on the second team last season.
The rest of the All-Rookie First Team consists of Los Angeles Lakers’ Kyle Kuzma, Chicago’s Lauri Markkanen, Utah’s Donovan Mitchell and Philadelphia’s Ben Simmons.
Mitchell and Simmons were unanimous first-teamers, while Tatum got one vote for second team and 99 for first team. Kuzma earned 93, and Markkanen 76 first-team votes.
The Second Team features Bogdan Bogdanovic of the Sacramento Kinds, John Collins of the Atlanta Hawks, Dennis Smith Jr. of the Dallas Mavericks and No. 2 overall pick Lonzo Ball of the Lakers.
The Celtics’ other rookie, Semi Ojeleye received one second-team vote.